网鼎杯-wp
signal
很简单的vm,甚至可以一位一位解
1 | int __cdecl main(int argc, const char **argv, const char **envp) |
vm_operad中包含了一些指令,很好理解,甚至不需要调试就可以看懂
1 | 0xA: read |
read函数进行了输入的一些控制
1 | size_t __cdecl read(char *a1) |
flag的长度为15位,再观察opcode,可以发现是一位一位进行处理,经过一种运算然后0x8暂存,然后再经过一种计算将结果写入最终target,所以可以有两种解法,可以一位一位的逆flag,也可以逆vm的指令
逐位计算
flag1
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20target = [0x22, 0x3F, 0x34, 0x32, 0x72, 0x33, 0x18, 0xA7, 0x31,
0xF1, 0x28, 0x84, 0xC1, 0x1E, 0x7A]
flag = ""
flag += chr((target[0] + 5) ^ 0x10)
flag += chr((target[1] // 3) ^ 0x20)
flag += chr((target[2] + 1) + 2)
flag += chr((target[3] - 1) ^ 4)
flag += chr((target[4] + 0x21)//3)
flag += chr(target[5] + 2)
flag += chr((target[6] + 0x20) ^ 0x9)
flag += chr((target[7] ^ 0x24) - 0x51)
flag += chr(target[8])
flag += chr((target[9] - 0x25) // 2)
flag += chr((target[10] ^ 0x41) - 0x36)
flag += chr(target[11] - 0x20)
flag += chr((target[12] - 0x25) // 3)
flag += chr((target[13] + 0x20) ^ 9)
flag += chr((target[14] - 1) - 0x41)
print(flag)
# 757515121f3d478调整
vm指令把每一个运算改成逆运算,然后将每一位的两次计算交换顺序
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175#include <iostream>
#include "ida.h"
using namespace std;
int __cdecl vm_operad(unsigned int *opcode, int len) {
int result; // eax
unsigned int input[100] = {0x22, 0x3F, 0x34, 0x32, 0x72, 0x33, 0x18, 0xA7, 0x31,
0xF1, 0x28, 0x84, 0xC1, 0x1E, 0x7A}; // [esp+13h] [ebp-E5h]
char v4[100] = {0}; // [esp+77h] [ebp-81h]
string flag;
unsigned char v5; // [esp+DBh] [ebp-1Dh]
int v6; // [esp+DCh] [ebp-1Ch]
int v7; // [esp+E0h] [ebp-18h]
int v8; // [esp+E4h] [ebp-14h]
int v9; // [esp+E8h] [ebp-10h]
int opcode_index; // [esp+ECh] [ebp-Ch]
opcode_index = 0;
v9 = 0;
v8 = 0;
v7 = 0;
v6 = 0;
while (true) {
result = opcode_index;
if (opcode_index >= len) {
cout << flag << endl;
return result;
}
switch (opcode[opcode_index]) {
case 1:
flag += v5;
++opcode_index;
++v7;
++v9;
break;
case 2:
v5 = input[v9] - opcode[opcode_index + 1];
opcode_index += 2;
break;
case 3:
v5 = input[v9] + LOBYTE(opcode[opcode_index + 1]);
opcode_index += 2;
break;
case 4:
v5 = opcode[opcode_index + 1] ^ input[v9];
opcode_index += 2;
break;
case 5:
v5 = input[v9] / opcode[opcode_index + 1];
opcode_index += 2;
break;
case 6:
++opcode_index;
break;
case 7:
++v8;
opcode_index += 2;
break;
case 8:
input[v6] = v5;
++opcode_index;
++v6;
break;
case 10:
// read(input);
++opcode_index;
break;
case 11:
v5 = input[v9] + 1;
++opcode_index;
break;
case 12:
v5 = input[v9] - 1;
++opcode_index;
break;
default:
continue;
}
}
}
unsigned int opcodes[114] = {
0x0000000A,
0x00000003, 0x00000005,
0x00000008,
0x00000004, 0x00000010,
0x00000001,
0x00000005, 0x00000003,
0x00000008,
0x00000004, 0x00000020,
0x00000001,
0x0000000B,
0x00000008,
0x00000003, 0x00000002,
0x00000001,
0x00000004, 0x00000004,
0x00000008,
0x0000000C,
0x00000001,
0x00000003, 0x00000021,
0x00000008,
0x00000005, 0x00000003,
0x00000001,
0x0000000B,
0x00000008,
0x0000000B,
0x00000001,
0x00000003, 0x00000020,
0x00000008,
0x00000004, 0x00000009,
0x00000001,
0x00000004, 0x00000024,
0x00000008,
0x00000002, 0x00000051,
0x00000001,
0x0000000B,
0x00000008,
0x0000000C,
0x00000001,
0x00000002, 0x00000025,
0x00000008,
0x00000005, 0x00000002,
0x00000001,
0x00000004, 0x00000041,
0x00000008,
0x00000002, 0x00000036,
0x00000001,
0x00000005, 0x00000001,
0x00000008,
0x00000002, 0x00000020,
0x00000001,
0x00000002, 0x00000025,
0x00000008,
0x00000005, 0x00000003,
0x00000001,
0x00000003, 0x00000020,
0x00000008,
0x00000004, 0x00000009,
0x00000001,
0x0000000C,
0x00000008,
0x00000002, 0x00000041,
0x00000001,
0x00000007, 0x00000022, 0x00000007, 0x0000003F,
0x00000007, 0x00000034, 0x00000007, 0x00000032, 0x00000007, 0x00000072, 0x00000007, 0x00000033,
0x00000007, 0x00000018, 0x00000007, 0xFFFFFFA7, 0x00000007, 0x00000031, 0x00000007, 0xFFFFFFF1,
0x00000007, 0x00000028, 0x00000007, 0xFFFFFF84, 0x00000007, 0xFFFFFFC1, 0x00000007, 0x0000001E,
0x00000007, 0x0000007A
};
int main() {
vm_operad(opcodes, 114);
}
// 757515121f3d478
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